1101312443041 has 4 divisors (see below), whose sum is σ = 1102625092800. Its totient is φ = 1099999793284.

The previous prime is 1101312443027. The next prime is 1101312443047. The reversal of 1101312443041 is 1403442131011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1101312443041 - 2²⁷ = 1101178225313 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1101312442997 and 1101312443015.

It is not an unprimeable number, because it can be changed into a prime (1101312443047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 656323621 + ... + 656325298.

It is an arithmetic number, because the mean of its divisors is an integer number (275656273200).

Almost surely, 2^{1101312443041} is an apocalyptic number.

It is an amenable number.

1101312443041 is a deficient number, since it is larger than the sum of its proper divisors (1312649759).

1101312443041 is an equidigital number, since it uses as much as digits as its factorization.

1101312443041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1312649758.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1101312443041 its reverse (1403442131011), we get a palindrome (2504754574052).

The spelling of 1101312443041 in words is "one trillion, one hundred one billion, three hundred twelve million, four hundred forty-three thousand, forty-one".