Base | Representation |
---|---|
bin | 11001000010101000101100… |
… | …100111110010010010001001 |
3 | 112102221112201100101201021102 |
4 | 121002220230213302102021 |
5 | 103413401422301443423 |
6 | 1030122025152351145 |
7 | 32124540030315143 |
oct | 3102505447622211 |
9 | 472845640351242 |
10 | 110132300031113 |
11 | 32100934251788 |
12 | 104284645454b5 |
13 | 495b57b82c339 |
14 | 1d2a608a85c93 |
15 | caebd9451c28 |
hex | 642a2c9f2489 |
110132300031113 has 2 divisors, whose sum is σ = 110132300031114. Its totient is φ = 110132300031112.
The previous prime is 110132300030939. The next prime is 110132300031157. The reversal of 110132300031113 is 311130003231011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 78001450776649 + 32130849254464 = 8831843^2 + 5668408^2 .
It is a cyclic number.
It is not a de Polignac number, because 110132300031113 - 222 = 110132295836809 is a prime.
It is not a weakly prime, because it can be changed into another prime (110132300030113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55066150015556 + 55066150015557.
It is an arithmetic number, because the mean of its divisors is an integer number (55066150015557).
Almost surely, 2110132300031113 is an apocalyptic number.
It is an amenable number.
110132300031113 is a deficient number, since it is larger than the sum of its proper divisors (1).
110132300031113 is an equidigital number, since it uses as much as digits as its factorization.
110132300031113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 110132300031113 its reverse (311130003231011), we get a palindrome (421262303262124).
The spelling of 110132300031113 in words is "one hundred ten trillion, one hundred thirty-two billion, three hundred million, thirty-one thousand, one hundred thirteen".
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