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11013301153 is a prime number
BaseRepresentation
bin10100100000111000…
…11010001110100001
31001102112110122222201
422100130122032201
5140023401114103
65020501133201
7536630341501
oct122034321641
931375418881
1011013301153
1147417a3188
1221743ba201
13106690395a
14766973a01
15446d1a51d
hex29071a3a1

11013301153 has 2 divisors, whose sum is σ = 11013301154. Its totient is φ = 11013301152.

The previous prime is 11013301099. The next prime is 11013301157. The reversal of 11013301153 is 35110331011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9225026209 + 1788274944 = 96047^2 + 42288^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11013301153 is a prime.

It is a super-2 number, since 2×110133011532 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11013301153.

It is not a weakly prime, because it can be changed into another prime (11013301157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506650576 + 5506650577.

It is an arithmetic number, because the mean of its divisors is an integer number (5506650577).

Almost surely, 211013301153 is an apocalyptic number.

It is an amenable number.

11013301153 is a deficient number, since it is larger than the sum of its proper divisors (1).

11013301153 is an equidigital number, since it uses as much as digits as its factorization.

11013301153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135, while the sum is 19.

Adding to 11013301153 its reverse (35110331011), we get a palindrome (46123632164).

The spelling of 11013301153 in words is "eleven billion, thirteen million, three hundred one thousand, one hundred fifty-three".