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11013304005553 = 19875542679419
BaseRepresentation
bin1010000001000011110000…
…0100101011001110110001
31102222212021002111011222211
42200100330010223032301
52420420221311134203
635231235250332121
72214453640312453
oct240207404531661
942885232434884
1011013304005553
113566796aa4223
12129a55128a041
1361b71c796aa5
142a10924382d3
1514173465bc6d
hexa043c12b3b1

11013304005553 has 4 divisors (see below), whose sum is σ = 11018846686960. Its totient is φ = 11007761324148.

The previous prime is 11013304005551. The next prime is 11013304005611. The reversal of 11013304005553 is 35550040331011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11013304005553 - 21 = 11013304005551 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11013304005551) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2771337723 + ... + 2771341696.

It is an arithmetic number, because the mean of its divisors is an integer number (2754711671740).

Almost surely, 211013304005553 is an apocalyptic number.

It is an amenable number.

11013304005553 is a deficient number, since it is larger than the sum of its proper divisors (5542681407).

11013304005553 is an equidigital number, since it uses as much as digits as its factorization.

11013304005553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5542681406.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 11013304005553 its reverse (35550040331011), we get a palindrome (46563344336564).

The spelling of 11013304005553 in words is "eleven trillion, thirteen billion, three hundred four million, five thousand, five hundred fifty-three".

Divisors: 1 1987 5542679419 11013304005553