Base | Representation |
---|---|
bin | 11001000010101001101110… |
… | …110110101101110111000011 |
3 | 112102221122120210100001020101 |
4 | 121002221232312231313003 |
5 | 103413411211234211121 |
6 | 1030122331325423231 |
7 | 32124606412411255 |
oct | 3102515666556703 |
9 | 472848523301211 |
10 | 110133411241411 |
11 | 321013545234a8 |
12 | 1042871470ab17 |
13 | 495b6c7b0671c |
14 | 1d2a6b24a1cd5 |
15 | caec51c9e491 |
hex | 642a6edaddc3 |
110133411241411 has 2 divisors, whose sum is σ = 110133411241412. Its totient is φ = 110133411241410.
The previous prime is 110133411241393. The next prime is 110133411241421. The reversal of 110133411241411 is 114142114331011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110133411241411 - 219 = 110133410717123 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 110133411241411.
It is not a weakly prime, because it can be changed into another prime (110133411241421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55066705620705 + 55066705620706.
It is an arithmetic number, because the mean of its divisors is an integer number (55066705620706).
Almost surely, 2110133411241411 is an apocalyptic number.
110133411241411 is a deficient number, since it is larger than the sum of its proper divisors (1).
110133411241411 is an equidigital number, since it uses as much as digits as its factorization.
110133411241411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 28.
Adding to 110133411241411 its reverse (114142114331011), we get a palindrome (224275525572422).
The spelling of 110133411241411 in words is "one hundred ten trillion, one hundred thirty-three billion, four hundred eleven million, two hundred forty-one thousand, four hundred eleven".
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