Base | Representation |
---|---|
bin | 10100100000111001… |
… | …10011101100010001 |
3 | 1001102112122222001211 |
4 | 22100130303230101 |
5 | 140023412433312 |
6 | 5020503300121 |
7 | 536631254545 |
oct | 122034635421 |
9 | 31375588054 |
10 | 11013405457 |
11 | 474186458a |
12 | 217444a641 |
13 | 106693c282 |
14 | 76699da25 |
15 | 446d3b3a7 |
hex | 290733b11 |
11013405457 has 2 divisors, whose sum is σ = 11013405458. Its totient is φ = 11013405456.
The previous prime is 11013405427. The next prime is 11013405467. The reversal of 11013405457 is 75450431011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8603675536 + 2409729921 = 92756^2 + 49089^2 .
It is a cyclic number.
It is not a de Polignac number, because 11013405457 - 223 = 11005016849 is a prime.
It is not a weakly prime, because it can be changed into another prime (11013405427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506702728 + 5506702729.
It is an arithmetic number, because the mean of its divisors is an integer number (5506702729).
Almost surely, 211013405457 is an apocalyptic number.
It is an amenable number.
11013405457 is a deficient number, since it is larger than the sum of its proper divisors (1).
11013405457 is an equidigital number, since it uses as much as digits as its factorization.
11013405457 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8400, while the sum is 31.
Adding to 11013405457 its reverse (75450431011), we get a palindrome (86463836468).
The spelling of 11013405457 in words is "eleven billion, thirteen million, four hundred five thousand, four hundred fifty-seven".
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