110141143113 has 4 divisors (see below), whose sum is σ = 146854857488. Its totient is φ = 73427428740.

The previous prime is 110141143097. The next prime is 110141143121. The reversal of 110141143113 is 311341141011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 110141143113 - 2⁴ = 110141143097 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 110141143113.

It is not an unprimeable number, because it can be changed into a prime (110141143613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18356857183 + ... + 18356857188.

It is an arithmetic number, because the mean of its divisors is an integer number (36713714372).

Almost surely, 2^110141143113 is an apocalyptic number.

It is an amenable number.

110141143113 is a deficient number, since it is larger than the sum of its proper divisors (36713714375).

110141143113 is an equidigital number, since it uses as much as digits as its factorization.

110141143113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36713714374.

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 110141143113 its reverse (311341141011), we get a palindrome (421482284124).

The spelling of 110141143113 in words is "one hundred ten billion, one hundred forty-one million, one hundred forty-three thousand, one hundred thirteen".