Base | Representation |
---|---|
bin | 110011010010011111… |
… | …1111101100111010011 |
3 | 101112022000101022122112 |
4 | 1212210333331213103 |
5 | 3301032424211032 |
6 | 122333154055535 |
7 | 10646301031325 |
oct | 1464477754723 |
9 | 345260338575 |
10 | 110142413267 |
11 | 42790580327 |
12 | 1941a57a5ab |
13 | a503b70803 |
14 | 548c095615 |
15 | 2ce98791b2 |
hex | 19a4ffd9d3 |
110142413267 has 2 divisors, whose sum is σ = 110142413268. Its totient is φ = 110142413266.
The previous prime is 110142413209. The next prime is 110142413327. The reversal of 110142413267 is 762314241011.
It is a weak prime.
It is an emirp because it is prime and its reverse (762314241011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110142413267 - 26 = 110142413203 is a prime.
It is a super-2 number, since 2×1101424132672 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (110142413207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55071206633 + 55071206634.
It is an arithmetic number, because the mean of its divisors is an integer number (55071206634).
Almost surely, 2110142413267 is an apocalyptic number.
110142413267 is a deficient number, since it is larger than the sum of its proper divisors (1).
110142413267 is an equidigital number, since it uses as much as digits as its factorization.
110142413267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 32.
Adding to 110142413267 its reverse (762314241011), we get a palindrome (872456654278).
The spelling of 110142413267 in words is "one hundred ten billion, one hundred forty-two million, four hundred thirteen thousand, two hundred sixty-seven".
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