Base | Representation |
---|---|
bin | 1010000001000111111101… |
… | …1011101111001101100011 |
3 | 1102222222011212000011221102 |
4 | 2200101333123233031203 |
5 | 2420430030113442033 |
6 | 35231543340545015 |
7 | 2214523642211345 |
oct | 240217733571543 |
9 | 42888155004842 |
10 | 11014434124643 |
11 | 3567216a10444 |
12 | 129a80785216b |
13 | 61b86c961a01 |
14 | 2a115c577295 |
15 | 14179d991de8 |
hex | a047f6ef363 |
11014434124643 has 2 divisors, whose sum is σ = 11014434124644. Its totient is φ = 11014434124642.
The previous prime is 11014434124613. The next prime is 11014434124651. The reversal of 11014434124643 is 34642143441011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11014434124643 - 26 = 11014434124579 is a prime.
It is a super-2 number, since 2×110144341246432 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11014434124597 and 11014434124606.
It is not a weakly prime, because it can be changed into another prime (11014434124613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5507217062321 + 5507217062322.
It is an arithmetic number, because the mean of its divisors is an integer number (5507217062322).
Almost surely, 211014434124643 is an apocalyptic number.
11014434124643 is a deficient number, since it is larger than the sum of its proper divisors (1).
11014434124643 is an equidigital number, since it uses as much as digits as its factorization.
11014434124643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 110592, while the sum is 38.
Adding to 11014434124643 its reverse (34642143441011), we get a palindrome (45656577565654).
The spelling of 11014434124643 in words is "eleven trillion, fourteen billion, four hundred thirty-four million, one hundred twenty-four thousand, six hundred forty-three".
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