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11014652014514 = 25507326007257
BaseRepresentation
bin1010000001001000110001…
…1010111010111110110010
31102222222202001000010122122
42200102030122322332302
52420431001403431024
635232021123034242
72214532226225651
oct240221432727662
942888661003578
1011014652014514
113567318a02315
12129a86880b982
1361b8a5b40b25
142a117d495198
151417b2b81d5e
hexa048c6bafb2

11014652014514 has 4 divisors (see below), whose sum is σ = 16521978021774. Its totient is φ = 5507326007256.

The previous prime is 11014652014481. The next prime is 11014652014547. The reversal of 11014652014514 is 41541025641011.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (11014652014481) and next prime (11014652014547).

It can be written as a sum of positive squares in only one way, i.e., 10576043838889 + 438608175625 = 3252083^2 + 662275^2 .

It is a super-3 number, since 3×110146520145143 (a number of 40 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2753663003627 + ... + 2753663003630.

Almost surely, 211014652014514 is an apocalyptic number.

11014652014514 is a deficient number, since it is larger than the sum of its proper divisors (5507326007260).

11014652014514 is an equidigital number, since it uses as much as digits as its factorization.

11014652014514 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5507326007259.

The product of its (nonzero) digits is 19200, while the sum is 35.

Adding to 11014652014514 its reverse (41541025641011), we get a palindrome (52555677655525).

The spelling of 11014652014514 in words is "eleven trillion, fourteen billion, six hundred fifty-two million, fourteen thousand, five hundred fourteen".

Divisors: 1 2 5507326007257 11014652014514