Base | Representation |
---|---|
bin | 1010000001011100101100… |
… | …1100101000010100001011 |
3 | 1110000111112202120002211121 |
4 | 2200113023030220110023 |
5 | 2421022430022344242 |
6 | 35234303533140111 |
7 | 2215111610112214 |
oct | 240271314502413 |
9 | 43014482502747 |
10 | 11020000199947 |
11 | 3569612905182 |
12 | 129b8bb92a637 |
13 | 61c248b6b9ab |
14 | 2a15298b040b |
15 | 1419c7464667 |
hex | a05cb32850b |
11020000199947 has 2 divisors, whose sum is σ = 11020000199948. Its totient is φ = 11020000199946.
The previous prime is 11020000199939. The next prime is 11020000199981. The reversal of 11020000199947 is 74999100002011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11020000199947 - 23 = 11020000199939 is a prime.
It is not a weakly prime, because it can be changed into another prime (11020000199987) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510000099973 + 5510000099974.
It is an arithmetic number, because the mean of its divisors is an integer number (5510000099974).
Almost surely, 211020000199947 is an apocalyptic number.
11020000199947 is a deficient number, since it is larger than the sum of its proper divisors (1).
11020000199947 is an equidigital number, since it uses as much as digits as its factorization.
11020000199947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40824, while the sum is 43.
The spelling of 11020000199947 in words is "eleven trillion, twenty billion, one hundred ninety-nine thousand, nine hundred forty-seven".
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