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1102011113131 = 3270733693433
BaseRepresentation
bin10000000010010100111…
…110110001111010101011
310220100111001022220022021
4100002110332301322223
5121023404321110011
62202131254405311
7142421601623065
oct20022476617253
93810431286267
101102011113131
113953a65a9065
121596b1360837
137cbc4643a46
143b4a2616735
151d9ec30b471
hex10094fb1eab

1102011113131 has 4 divisors (see below), whose sum is σ = 1102044839272. Its totient is φ = 1101977386992.

The previous prime is 1102011113107. The next prime is 1102011113173. The reversal of 1102011113131 is 1313111102011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1102011113131 - 29 = 1102011112619 is a prime.

It is a super-2 number, since 2×11020111131312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1102011113101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16814010 + ... + 16879423.

It is an arithmetic number, because the mean of its divisors is an integer number (275511209818).

Almost surely, 21102011113131 is an apocalyptic number.

1102011113131 is a deficient number, since it is larger than the sum of its proper divisors (33726141).

1102011113131 is an equidigital number, since it uses as much as digits as its factorization.

1102011113131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33726140.

The product of its (nonzero) digits is 18, while the sum is 16.

Adding to 1102011113131 its reverse (1313111102011), we get a palindrome (2415122215142).

The spelling of 1102011113131 in words is "one trillion, one hundred two billion, eleven million, one hundred thirteen thousand, one hundred thirty-one".

Divisors: 1 32707 33693433 1102011113131