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11020140240113 is a prime number
BaseRepresentation
bin1010000001011101001110…
…0010110101110011110001
31110000111220112001212211102
42200113103202311303301
52421023221400140423
635234325454454145
72215115230330454
oct240272342656361
943014815055742
1011020140240113
113569684964454
12129b93a804355
1361c26bb913b4
142a154032549b
151419d48c7c28
hexa05d38b5cf1

11020140240113 has 2 divisors, whose sum is σ = 11020140240114. Its totient is φ = 11020140240112.

The previous prime is 11020140240017. The next prime is 11020140240119. The reversal of 11020140240113 is 31104204102011.

11020140240113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9002922237169 + 2017218002944 = 3000487^2 + 1420288^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11020140240113 is a prime.

It is not a weakly prime, because it can be changed into another prime (11020140240119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510070120056 + 5510070120057.

It is an arithmetic number, because the mean of its divisors is an integer number (5510070120057).

Almost surely, 211020140240113 is an apocalyptic number.

It is an amenable number.

11020140240113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11020140240113 is an equidigital number, since it uses as much as digits as its factorization.

11020140240113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 11020140240113 its reverse (31104204102011), we get a palindrome (42124344342124).

The spelling of 11020140240113 in words is "eleven trillion, twenty billion, one hundred forty million, two hundred forty thousand, one hundred thirteen".