Base | Representation |
---|---|
bin | 1010000001011101101000… |
… | …1011110000111000110001 |
3 | 1110000112012021200010121111 |
4 | 2200113122023300320301 |
5 | 2421023433404144103 |
6 | 35234344514153321 |
7 | 2215121052204622 |
oct | 240273213607061 |
9 | 43015167603544 |
10 | 11020251631153 |
11 | 3569731826166 |
12 | 129b96bb82841 |
13 | 61c288c9295b |
14 | 2a155103da49 |
15 | 1419de57c86d |
hex | a05da2f0e31 |
11020251631153 has 2 divisors, whose sum is σ = 11020251631154. Its totient is φ = 11020251631152.
The previous prime is 11020251631139. The next prime is 11020251631159. The reversal of 11020251631153 is 35113615202011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7304733236529 + 3715518394624 = 2702727^2 + 1927568^2 .
It is a cyclic number.
It is not a de Polignac number, because 11020251631153 - 233 = 11011661696561 is a prime.
It is not a weakly prime, because it can be changed into another prime (11020251631159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510125815576 + 5510125815577.
It is an arithmetic number, because the mean of its divisors is an integer number (5510125815577).
Almost surely, 211020251631153 is an apocalyptic number.
It is an amenable number.
11020251631153 is a deficient number, since it is larger than the sum of its proper divisors (1).
11020251631153 is an equidigital number, since it uses as much as digits as its factorization.
11020251631153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 31.
Adding to 11020251631153 its reverse (35113615202011), we get a palindrome (46133866833164).
The spelling of 11020251631153 in words is "eleven trillion, twenty billion, two hundred fifty-one million, six hundred thirty-one thousand, one hundred fifty-three".
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