Base | Representation |
---|---|
bin | 10000000010011010010… |
… | …010000000110110100011 |
3 | 10220100201020122220120121 |
4 | 100002122102000312203 |
5 | 121024100102303443 |
6 | 2202144152421111 |
7 | 142424031532264 |
oct | 20023222006643 |
9 | 3810636586517 |
10 | 1102100041123 |
11 | 395441817a74 |
12 | 1597170a7797 |
13 | 7cc09baba63 |
14 | 3b4b036496b |
15 | 1da050254ed |
hex | 1009a480da3 |
1102100041123 has 2 divisors, whose sum is σ = 1102100041124. Its totient is φ = 1102100041122.
The previous prime is 1102100041109. The next prime is 1102100041127. The reversal of 1102100041123 is 3211400012011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1102100041123 is a prime.
It is a super-2 number, since 2×11021000411232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1102100041097 and 1102100041106.
It is not a weakly prime, because it can be changed into another prime (1102100041127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551050020561 + 551050020562.
It is an arithmetic number, because the mean of its divisors is an integer number (551050020562).
Almost surely, 21102100041123 is an apocalyptic number.
1102100041123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102100041123 is an equidigital number, since it uses as much as digits as its factorization.
1102100041123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1102100041123 its reverse (3211400012011), we get a palindrome (4313500053134).
The spelling of 1102100041123 in words is "one trillion, one hundred two billion, one hundred million, forty-one thousand, one hundred twenty-three".
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