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110210010193 is a prime number
BaseRepresentation
bin110011010100100000…
…1110100110001010001
3101112110201120121012101
41212221001310301101
53301202230311233
6122344011000401
710651051426033
oct1465101646121
9345421517171
10110210010193
114281574a958
1219439139101
13a514b7a5aa
14549704dc53
152d0077cc7d
hex19a9074c51

110210010193 has 2 divisors, whose sum is σ = 110210010194. Its totient is φ = 110210010192.

The previous prime is 110210010149. The next prime is 110210010223. The reversal of 110210010193 is 391010012011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85142571264 + 25067438929 = 291792^2 + 158327^2 .

It is an emirp because it is prime and its reverse (391010012011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110210010193 - 225 = 110176455761 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 110210010193.

It is not a weakly prime, because it can be changed into another prime (110210010293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55105005096 + 55105005097.

It is an arithmetic number, because the mean of its divisors is an integer number (55105005097).

Almost surely, 2110210010193 is an apocalyptic number.

It is an amenable number.

110210010193 is a deficient number, since it is larger than the sum of its proper divisors (1).

110210010193 is an equidigital number, since it uses as much as digits as its factorization.

110210010193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 19.

The spelling of 110210010193 in words is "one hundred ten billion, two hundred ten million, ten thousand, one hundred ninety-three".