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11021143313 is a prime number
BaseRepresentation
bin10100100001110100…
…10100110100010001
31001110002020002102002
422100322110310101
5140032403041223
65021341203345
7540054113105
oct122072246421
931402202362
1011021143313
11474616a104
122176b60555
13106841b29b
14767a15905
15447868e28
hex290e94d11

11021143313 has 2 divisors, whose sum is σ = 11021143314. Its totient is φ = 11021143312.

The previous prime is 11021143283. The next prime is 11021143321. The reversal of 11021143313 is 31334112011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10146935824 + 874207489 = 100732^2 + 29567^2 .

It is an emirp because it is prime and its reverse (31334112011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11021143313 - 216 = 11021077777 is a prime.

It is not a weakly prime, because it can be changed into another prime (11021143213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510571656 + 5510571657.

It is an arithmetic number, because the mean of its divisors is an integer number (5510571657).

Almost surely, 211021143313 is an apocalyptic number.

It is an amenable number.

11021143313 is a deficient number, since it is larger than the sum of its proper divisors (1).

11021143313 is an equidigital number, since it uses as much as digits as its factorization.

11021143313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 11021143313 its reverse (31334112011), we get a palindrome (42355255324).

The spelling of 11021143313 in words is "eleven billion, twenty-one million, one hundred forty-three thousand, three hundred thirteen".