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110212000057 is a prime number
BaseRepresentation
bin110011010100100100…
…1011010100100111001
3101112110212022200210001
41212221021122210321
53301203233000212
6122344121353001
710651104354265
oct1465111324471
9345425280701
10110212000057
1142816889975
1219439938761
13a5153c6223
14549740b0a5
152d00a22657
hex19a925a939

110212000057 has 2 divisors, whose sum is σ = 110212000058. Its totient is φ = 110212000056.

The previous prime is 110212000049. The next prime is 110212000091. The reversal of 110212000057 is 750000212011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 101290064121 + 8921935936 = 318261^2 + 94456^2 .

It is a cyclic number.

It is not a de Polignac number, because 110212000057 - 23 = 110212000049 is a prime.

It is a super-3 number, since 3×1102120000573 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110211999998 and 110212000043.

It is not a weakly prime, because it can be changed into another prime (110212000027) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55106000028 + 55106000029.

It is an arithmetic number, because the mean of its divisors is an integer number (55106000029).

Almost surely, 2110212000057 is an apocalyptic number.

It is an amenable number.

110212000057 is a deficient number, since it is larger than the sum of its proper divisors (1).

110212000057 is an equidigital number, since it uses as much as digits as its factorization.

110212000057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 140, while the sum is 19.

Adding to 110212000057 its reverse (750000212011), we get a palindrome (860212212068).

The spelling of 110212000057 in words is "one hundred ten billion, two hundred twelve million, fifty-seven", and thus it is an aban number.