Base | Representation |
---|---|
bin | 1010000001100001100101… |
… | …1101010111101101100001 |
3 | 1110000121221021012222201020 |
4 | 2200120121131113231201 |
5 | 2421033122140224413 |
6 | 35235042115400053 |
7 | 2215156262403363 |
oct | 240303135275541 |
9 | 43017837188636 |
10 | 11021313211233 |
11 | 356a126a89a76 |
12 | 12a00075b3029 |
13 | 61c3c7bb1050 |
14 | 2a161201ad33 |
15 | 141a52874c23 |
hex | a0619757b61 |
11021313211233 has 16 divisors (see below), whose sum is σ = 15881395803840. Its totient is φ = 6758380695744.
The previous prime is 11021313211231. The next prime is 11021313211241. The reversal of 11021313211233 is 33211231312011.
It is not a de Polignac number, because 11021313211233 - 21 = 11021313211231 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11021313211231) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 499278318 + ... + 499300391.
It is an arithmetic number, because the mean of its divisors is an integer number (992587237740).
Almost surely, 211021313211233 is an apocalyptic number.
11021313211233 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
11021313211233 is a deficient number, since it is larger than the sum of its proper divisors (4860082592607).
11021313211233 is a wasteful number, since it uses less digits than its factorization.
11021313211233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 998579008.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 11021313211233 its reverse (33211231312011), we get a palindrome (44232544523244).
The spelling of 11021313211233 in words is "eleven trillion, twenty-one billion, three hundred thirteen million, two hundred eleven thousand, two hundred thirty-three".
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