Base | Representation |
---|---|
bin | 1010000001100100001001… |
… | …1010000110011100011011 |
3 | 1110000200201010221122110211 |
4 | 2200121002122012130123 |
5 | 2421041024024014211 |
6 | 35235234220351551 |
7 | 2215212304026241 |
oct | 240310232063433 |
9 | 43020633848424 |
10 | 11022000219931 |
11 | 356a449865858 |
12 | 12a01796a55b7 |
13 | 61c4a732217c |
14 | 2a1679372791 |
15 | 141a92d2ce21 |
hex | a064268671b |
11022000219931 has 2 divisors, whose sum is σ = 11022000219932. Its totient is φ = 11022000219930.
The previous prime is 11022000219869. The next prime is 11022000220031. The reversal of 11022000219931 is 13991200022011.
It is a weak prime.
It is an emirp because it is prime and its reverse (13991200022011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11022000219931 - 237 = 10884561266459 is a prime.
It is a super-2 number, since 2×110220002199312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11022000219893 and 11022000219902.
It is not a weakly prime, because it can be changed into another prime (11022000219331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5511000109965 + 5511000109966.
It is an arithmetic number, because the mean of its divisors is an integer number (5511000109966).
Almost surely, 211022000219931 is an apocalyptic number.
11022000219931 is a deficient number, since it is larger than the sum of its proper divisors (1).
11022000219931 is an equidigital number, since it uses as much as digits as its factorization.
11022000219931 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 31.
The spelling of 11022000219931 in words is "eleven trillion, twenty-two billion, two hundred nineteen thousand, nine hundred thirty-one".
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