Base | Representation |
---|---|
bin | 10000000010100000010… |
… | …011101001000110001011 |
3 | 10220100222021212211101001 |
4 | 100002200103221012023 |
5 | 121024301442201103 |
6 | 2202202203235431 |
7 | 142426400015161 |
oct | 20024023510613 |
9 | 3810867784331 |
10 | 1102201131403 |
11 | 395493893659 |
12 | 159744b18b77 |
13 | 7cc24b148a8 |
14 | 3b4bd95b231 |
15 | 1da0dd4301d |
hex | 100a04e918b |
1102201131403 has 2 divisors, whose sum is σ = 1102201131404. Its totient is φ = 1102201131402.
The previous prime is 1102201131377. The next prime is 1102201131433. The reversal of 1102201131403 is 3041311022011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1102201131403 - 225 = 1102167576971 is a prime.
It is not a weakly prime, because it can be changed into another prime (1102201131433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551100565701 + 551100565702.
It is an arithmetic number, because the mean of its divisors is an integer number (551100565702).
Almost surely, 21102201131403 is an apocalyptic number.
1102201131403 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102201131403 is an equidigital number, since it uses as much as digits as its factorization.
1102201131403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1102201131403 its reverse (3041311022011), we get a palindrome (4143512153414).
The spelling of 1102201131403 in words is "one trillion, one hundred two billion, two hundred one million, one hundred thirty-one thousand, four hundred three".
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