Base | Representation |
---|---|
bin | 11001000011111010100101… |
… | …001011110111011010001011 |
3 | 112110020221122210021122100001 |
4 | 121003322211023313122023 |
5 | 103421322003324214011 |
6 | 1030230245423423431 |
7 | 32134101565504612 |
oct | 3103724513673213 |
9 | 473227583248301 |
10 | 110220222101131 |
11 | 32135151a3926a |
12 | 10441501454b77 |
13 | 4966950cc013c |
14 | 1d30989a00879 |
15 | cb21331757c1 |
hex | 643ea52f768b |
110220222101131 has 2 divisors, whose sum is σ = 110220222101132. Its totient is φ = 110220222101130.
The previous prime is 110220222101081. The next prime is 110220222101137. The reversal of 110220222101131 is 131101222022011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110220222101131 - 221 = 110220220003979 is a prime.
It is a super-2 number, since 2×1102202221011312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 110220222101099 and 110220222101108.
It is not a weakly prime, because it can be changed into another prime (110220222101137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55110111050565 + 55110111050566.
It is an arithmetic number, because the mean of its divisors is an integer number (55110111050566).
Almost surely, 2110220222101131 is an apocalyptic number.
110220222101131 is a deficient number, since it is larger than the sum of its proper divisors (1).
110220222101131 is an equidigital number, since it uses as much as digits as its factorization.
110220222101131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 110220222101131 its reverse (131101222022011), we get a palindrome (241321444123142).
The spelling of 110220222101131 in words is "one hundred ten trillion, two hundred twenty billion, two hundred twenty-two million, one hundred one thousand, one hundred thirty-one".
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