Base | Representation |
---|---|
bin | 1010000001101000010010… |
… | …0100000011000110101011 |
3 | 1110000210120111102121112222 |
4 | 2200122010210003012223 |
5 | 2421100312142431242 |
6 | 35235540305424255 |
7 | 2215251642042065 |
oct | 240320444030653 |
9 | 43023514377488 |
10 | 11023110123947 |
11 | 356a9693250a9 |
12 | 12a042933b08b |
13 | 61c62325cacc |
14 | 2a174292c735 |
15 | 141b0a4bd5d2 |
hex | a06849031ab |
11023110123947 has 2 divisors, whose sum is σ = 11023110123948. Its totient is φ = 11023110123946.
The previous prime is 11023110123929. The next prime is 11023110124001. The reversal of 11023110123947 is 74932101132011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11023110123947 - 210 = 11023110122923 is a prime.
It is not a weakly prime, because it can be changed into another prime (11023110113947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5511555061973 + 5511555061974.
It is an arithmetic number, because the mean of its divisors is an integer number (5511555061974).
Almost surely, 211023110123947 is an apocalyptic number.
11023110123947 is a deficient number, since it is larger than the sum of its proper divisors (1).
11023110123947 is an equidigital number, since it uses as much as digits as its factorization.
11023110123947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 35.
Adding to 11023110123947 its reverse (74932101132011), we get a palindrome (85955211255958).
The spelling of 11023110123947 in words is "eleven trillion, twenty-three billion, one hundred ten million, one hundred twenty-three thousand, nine hundred forty-seven".
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