Base | Representation |
---|---|
bin | 1010000001101000010011… |
… | …0000001101101101100011 |
3 | 1110000210120201102122021121 |
4 | 2200122010300031231203 |
5 | 2421100314002004443 |
6 | 35235540502033111 |
7 | 2215252011124012 |
oct | 240320460155543 |
9 | 43023521378247 |
10 | 11023113313123 |
11 | 356a97010318a |
12 | 12a042a418797 |
13 | 61c623b085b2 |
14 | 2a174311ca79 |
15 | 141b0a8ed4ed |
hex | a0684c0db63 |
11023113313123 has 2 divisors, whose sum is σ = 11023113313124. Its totient is φ = 11023113313122.
The previous prime is 11023113313097. The next prime is 11023113313141. The reversal of 11023113313123 is 32131331132011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11023113313123 is a prime.
It is a super-3 number, since 3×110231133131233 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (11023113713123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5511556656561 + 5511556656562.
It is an arithmetic number, because the mean of its divisors is an integer number (5511556656562).
Almost surely, 211023113313123 is an apocalyptic number.
11023113313123 is a deficient number, since it is larger than the sum of its proper divisors (1).
11023113313123 is an equidigital number, since it uses as much as digits as its factorization.
11023113313123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 11023113313123 its reverse (32131331132011), we get a palindrome (43154444445134).
The spelling of 11023113313123 in words is "eleven trillion, twenty-three billion, one hundred thirteen million, three hundred thirteen thousand, one hundred twenty-three".
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