Base | Representation |
---|---|
bin | 1010000001101000011101… |
… | …0001010101110100101011 |
3 | 1110000210200122220120111002 |
4 | 2200122013101111310223 |
5 | 2421100410310122111 |
6 | 35235545011225215 |
7 | 2215253033134034 |
oct | 240320721256453 |
9 | 43023618816432 |
10 | 11023155551531 |
11 | 356a991a32562 |
12 | 12a04405a820b |
13 | 61c62c7a6c36 |
14 | 2a1748995a8b |
15 | 141b0e49363b |
hex | a0687455d2b |
11023155551531 has 2 divisors, whose sum is σ = 11023155551532. Its totient is φ = 11023155551530.
The previous prime is 11023155551497. The next prime is 11023155551623. The reversal of 11023155551531 is 13515555132011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11023155551531 - 210 = 11023155550507 is a prime.
It is a super-2 number, since 2×110231555515312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11023155551231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5511577775765 + 5511577775766.
It is an arithmetic number, because the mean of its divisors is an integer number (5511577775766).
Almost surely, 211023155551531 is an apocalyptic number.
11023155551531 is a deficient number, since it is larger than the sum of its proper divisors (1).
11023155551531 is an equidigital number, since it uses as much as digits as its factorization.
11023155551531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56250, while the sum is 38.
The spelling of 11023155551531 in words is "eleven trillion, twenty-three billion, one hundred fifty-five million, five hundred fifty-one thousand, five hundred thirty-one".
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