Search a number
-
+
1102322213233 is a prime number
BaseRepresentation
bin10000000010100111100…
…001100010000101110001
310220101021201201102102021
4100002213201202011301
5121030023441310413
62202222210351441
7142432400133343
oct20024741420561
93811251642367
101102322213233
1139554617418a
1215977958b581
137cc43c2a047
143b4d1a79293
151da197ae18d
hex100a7862171

1102322213233 has 2 divisors, whose sum is σ = 1102322213234. Its totient is φ = 1102322213232.

The previous prime is 1102322213207. The next prime is 1102322213257. The reversal of 1102322213233 is 3323122232011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1028342021184 + 73980192049 = 1014072^2 + 271993^2 .

It is a cyclic number.

It is not a de Polignac number, because 1102322213233 - 217 = 1102322082161 is a prime.

It is a super-2 number, since 2×11023222132332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1102322213198 and 1102322213207.

It is not a weakly prime, because it can be changed into another prime (1102322213033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551161106616 + 551161106617.

It is an arithmetic number, because the mean of its divisors is an integer number (551161106617).

Almost surely, 21102322213233 is an apocalyptic number.

It is an amenable number.

1102322213233 is a deficient number, since it is larger than the sum of its proper divisors (1).

1102322213233 is an equidigital number, since it uses as much as digits as its factorization.

1102322213233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1102322213233 its reverse (3323122232011), we get a palindrome (4425444445244).

The spelling of 1102322213233 in words is "one trillion, one hundred two billion, three hundred twenty-two million, two hundred thirteen thousand, two hundred thirty-three".