Base | Representation |
---|---|
bin | 110011010101010001… |
… | …0010110011111101001 |
3 | 101112112111012011201002 |
4 | 1212222202112133221 |
5 | 3301230220023103 |
6 | 122350313204345 |
7 | 10651506465356 |
oct | 1465242263751 |
9 | 345474164632 |
10 | 110235314153 |
11 | 42828a63118 |
12 | 194457006b5 |
13 | a51a199c53 |
14 | 549a55962d |
15 | 2d02aca488 |
hex | 19aa8967e9 |
110235314153 has 2 divisors, whose sum is σ = 110235314154. Its totient is φ = 110235314152.
The previous prime is 110235314099. The next prime is 110235314177. The reversal of 110235314153 is 351413532011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 61074225424 + 49161088729 = 247132^2 + 221723^2 .
It is an emirp because it is prime and its reverse (351413532011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110235314153 - 210 = 110235313129 is a prime.
It is not a weakly prime, because it can be changed into another prime (110235314653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55117657076 + 55117657077.
It is an arithmetic number, because the mean of its divisors is an integer number (55117657077).
Almost surely, 2110235314153 is an apocalyptic number.
It is an amenable number.
110235314153 is a deficient number, since it is larger than the sum of its proper divisors (1).
110235314153 is an equidigital number, since it uses as much as digits as its factorization.
110235314153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 110235314153 its reverse (351413532011), we get a palindrome (461648846164).
The spelling of 110235314153 in words is "one hundred ten billion, two hundred thirty-five million, three hundred fourteen thousand, one hundred fifty-three".
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