Base | Representation |
---|---|
bin | 1010000001101011110010… |
… | …1010111000100110110011 |
3 | 1110000220000002200102111101 |
4 | 2200122330222320212303 |
5 | 2421104224132040201 |
6 | 35240213533225231 |
7 | 2215314162066646 |
oct | 240327452704663 |
9 | 43026002612441 |
10 | 11024051440051 |
11 | 35703017068a1 |
12 | 12a0650632217 |
13 | 61c7432910a0 |
14 | 2a17d1961a5d |
15 | 141b62e5bd01 |
hex | a06bcab89b3 |
11024051440051 has 32 divisors (see below), whose sum is σ = 12114149104512. Its totient is φ = 9969124239360.
The previous prime is 11024051440001. The next prime is 11024051440063. The reversal of 11024051440051 is 15004415042011.
11024051440051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11024051440051 - 219 = 11024050915763 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11024051440001) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2417022811 + ... + 2417027371.
It is an arithmetic number, because the mean of its divisors is an integer number (378567159516).
Almost surely, 211024051440051 is an apocalyptic number.
11024051440051 is a deficient number, since it is larger than the sum of its proper divisors (1090097664461).
11024051440051 is a wasteful number, since it uses less digits than its factorization.
11024051440051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9103.
The product of its (nonzero) digits is 3200, while the sum is 28.
Adding to 11024051440051 its reverse (15004415042011), we get a palindrome (26028466482062).
The spelling of 11024051440051 in words is "eleven trillion, twenty-four billion, fifty-one million, four hundred forty thousand, fifty-one".
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