Base | Representation |
---|---|
bin | 10100100010001101… |
… | …10111110000000011 |
3 | 1001110022102011211011 |
4 | 22101012313300003 |
5 | 140034223312011 |
6 | 5021535501351 |
7 | 540124061356 |
oct | 122106676003 |
9 | 31408364734 |
10 | 11024432131 |
11 | 4748006039 |
12 | 2178087857 |
13 | 106900022b |
14 | 76823029d |
15 | 447cb8621 |
hex | 2911b7c03 |
11024432131 has 4 divisors (see below), whose sum is σ = 11024683264. Its totient is φ = 11024181000.
The previous prime is 11024432129. The next prime is 11024432137. The reversal of 11024432131 is 13123442011.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13123442011 = 1123 ⋅11686057.
It is a cyclic number.
It is not a de Polignac number, because 11024432131 - 21 = 11024432129 is a prime.
It is a super-2 number, since 2×110244321312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11024432137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40515 + ... + 153916.
It is an arithmetic number, because the mean of its divisors is an integer number (2756170816).
Almost surely, 211024432131 is an apocalyptic number.
11024432131 is a deficient number, since it is larger than the sum of its proper divisors (251133).
11024432131 is an equidigital number, since it uses as much as digits as its factorization.
11024432131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 251132.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 11024432131 its reverse (13123442011), we get a palindrome (24147874142).
The spelling of 11024432131 in words is "eleven billion, twenty-four million, four hundred thirty-two thousand, one hundred thirty-one".
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