Base | Representation |
---|---|
bin | 110011010111001101… |
… | …0010101010101011001 |
3 | 101112201000111212111021 |
4 | 1212232122111111121 |
5 | 3301343340233423 |
6 | 122400554402441 |
7 | 10653226155133 |
oct | 1465632252531 |
9 | 345630455437 |
10 | 110300321113 |
11 | 42861723884 |
12 | 19463430421 |
13 | a52a7aabc8 |
14 | 54a503c053 |
15 | 2d0866b95d |
hex | 19ae695559 |
110300321113 has 2 divisors, whose sum is σ = 110300321114. Its totient is φ = 110300321112.
The previous prime is 110300321093. The next prime is 110300321137. The reversal of 110300321113 is 311123003011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 80436333769 + 29863987344 = 283613^2 + 172812^2 .
It is an emirp because it is prime and its reverse (311123003011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110300321113 - 213 = 110300312921 is a prime.
It is not a weakly prime, because it can be changed into another prime (110300321143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55150160556 + 55150160557.
It is an arithmetic number, because the mean of its divisors is an integer number (55150160557).
Almost surely, 2110300321113 is an apocalyptic number.
It is an amenable number.
110300321113 is a deficient number, since it is larger than the sum of its proper divisors (1).
110300321113 is an equidigital number, since it uses as much as digits as its factorization.
110300321113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 110300321113 its reverse (311123003011), we get a palindrome (421423324124).
The spelling of 110300321113 in words is "one hundred ten billion, three hundred million, three hundred twenty-one thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •