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11030110000233 = 33676703333411
BaseRepresentation
bin1010000010000010010111…
…0010011101010001101001
31110001110122022221011122020
42200200211302131101221
52421204131130001413
635243055041215053
72215620260024502
oct240404562352151
943043568834566
1011030110000233
1135729305a4825
1212a1861631489
1362019a52163c
142a1c08455ba9
15141db9cb0c23
hexa0825c9d469

11030110000233 has 4 divisors (see below), whose sum is σ = 14706813333648. Its totient is φ = 7353406666820.

The previous prime is 11030110000201. The next prime is 11030110000307. The reversal of 11030110000233 is 33200001103011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11030110000233 - 25 = 11030110000201 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11030110000033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1838351666703 + ... + 1838351666708.

It is an arithmetic number, because the mean of its divisors is an integer number (3676703333412).

Almost surely, 211030110000233 is an apocalyptic number.

It is an amenable number.

11030110000233 is a deficient number, since it is larger than the sum of its proper divisors (3676703333415).

11030110000233 is an equidigital number, since it uses as much as digits as its factorization.

11030110000233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3676703333414.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 11030110000233 its reverse (33200001103011), we get a palindrome (44230111103244).

The spelling of 11030110000233 in words is "eleven trillion, thirty billion, one hundred ten million, two hundred thirty-three", and thus it is an aban number.

Divisors: 1 3 3676703333411 11030110000233