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11030311113 = 33676770371
BaseRepresentation
bin10100100010111010…
…10011000011001001
31001110201110212021020
422101131103003021
5140042224423423
65022305503053
7540225045303
oct122135230311
931421425236
1011030311113
114750360aa8
12217a041a89
13106a2ab113
14768d20973
1544857a4e3
hex2917530c9

11030311113 has 4 divisors (see below), whose sum is σ = 14707081488. Its totient is φ = 7353540740.

The previous prime is 11030311111. The next prime is 11030311141. The reversal of 11030311113 is 31111303011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11030311113 - 21 = 11030311111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11030311092 and 11030311101.

It is not an unprimeable number, because it can be changed into a prime (11030311111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1838385183 + ... + 1838385188.

It is an arithmetic number, because the mean of its divisors is an integer number (3676770372).

Almost surely, 211030311113 is an apocalyptic number.

It is an amenable number.

11030311113 is a deficient number, since it is larger than the sum of its proper divisors (3676770375).

11030311113 is an equidigital number, since it uses as much as digits as its factorization.

11030311113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3676770374.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 11030311113 its reverse (31111303011), we get a palindrome (42141614124).

The spelling of 11030311113 in words is "eleven billion, thirty million, three hundred eleven thousand, one hundred thirteen".

Divisors: 1 3 3676770371 11030311113