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11030413502114 = 25515206751057
BaseRepresentation
bin1010000010000011011111…
…1000001110011010100010
31110001111102111000122221122
42200200313320032122202
52421210241324031424
635243145122252242
72215630633530566
oct240406770163242
943044374018848
1011030413502114
113572a76950226
1212a19271b7082
13620218377356
142a1c3689b6a6
15141dd676245e
hexa0837e0e6a2

11030413502114 has 4 divisors (see below), whose sum is σ = 16545620253174. Its totient is φ = 5515206751056.

The previous prime is 11030413502113. The next prime is 11030413502123. The reversal of 11030413502114 is 41120531403011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 9542952753889 + 1487460748225 = 3089167^2 + 1219615^2 .

It is not an unprimeable number, because it can be changed into a prime (11030413502113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2757603375527 + ... + 2757603375530.

Almost surely, 211030413502114 is an apocalyptic number.

11030413502114 is a deficient number, since it is larger than the sum of its proper divisors (5515206751060).

11030413502114 is an equidigital number, since it uses as much as digits as its factorization.

11030413502114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5515206751059.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 11030413502114 its reverse (41120531403011), we get a palindrome (52150944905125).

The spelling of 11030413502114 in words is "eleven trillion, thirty billion, four hundred thirteen million, five hundred two thousand, one hundred fourteen".

Divisors: 1 2 5515206751057 11030413502114