Base | Representation |
---|---|
bin | 1010000010000101101110… |
… | …1011110111011101000010 |
3 | 1110001112222100102102022021 |
4 | 2200201123223313131002 |
5 | 2421213004121221424 |
6 | 35243324502232054 |
7 | 2215651546661266 |
oct | 240413353673502 |
9 | 43045870372267 |
10 | 11031014242114 |
11 | 3573254a64069 |
12 | 12a1a7442562a |
13 | 6202b29719c9 |
14 | 2a1c925980a6 |
15 | 141e1e3794e4 |
hex | a085baf7742 |
11031014242114 has 4 divisors (see below), whose sum is σ = 16546521363174. Its totient is φ = 5515507121056.
The previous prime is 11031014242099. The next prime is 11031014242169. The reversal of 11031014242114 is 41124241013011.
11031014242114 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 6775437203089 + 4255577039025 = 2602967^2 + 2062905^2 .
It is a super-2 number, since 2×110310142421142 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2757753560527 + ... + 2757753560530.
Almost surely, 211031014242114 is an apocalyptic number.
11031014242114 is a deficient number, since it is larger than the sum of its proper divisors (5515507121060).
11031014242114 is an equidigital number, since it uses as much as digits as its factorization.
11031014242114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5515507121059.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 11031014242114 its reverse (41124241013011), we get a palindrome (52155255255125).
The spelling of 11031014242114 in words is "eleven trillion, thirty-one billion, fourteen million, two hundred forty-two thousand, one hundred fourteen".
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