Search a number
-
+
110311021307 is a prime number
BaseRepresentation
bin110011010111100001…
…1001001101011111011
3101112201202122111101202
41212233003021223323
53301404110140212
6122402020004415
710653416132054
oct1465703115373
9345652574352
10110311021307
1142867772013
1219466b3070b
13a52ca86396
1454a662572b
152d095820c2
hex19af0c9afb

110311021307 has 2 divisors, whose sum is σ = 110311021308. Its totient is φ = 110311021306.

The previous prime is 110311021297. The next prime is 110311021363. The reversal of 110311021307 is 703120113011.

It is a weak prime.

It is an emirp because it is prime and its reverse (703120113011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110311021307 - 24 = 110311021291 is a prime.

It is a super-3 number, since 3×1103110213073 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (110311021507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55155510653 + 55155510654.

It is an arithmetic number, because the mean of its divisors is an integer number (55155510654).

Almost surely, 2110311021307 is an apocalyptic number.

110311021307 is a deficient number, since it is larger than the sum of its proper divisors (1).

110311021307 is an equidigital number, since it uses as much as digits as its factorization.

110311021307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 126, while the sum is 20.

Adding to 110311021307 its reverse (703120113011), we get a palindrome (813431134318).

The spelling of 110311021307 in words is "one hundred ten billion, three hundred eleven million, twenty-one thousand, three hundred seven".