Base | Representation |
---|---|
bin | 1010000010000110001001… |
… | …0000000111111010110011 |
3 | 1110001120021000201112021122 |
4 | 2200201202100013322303 |
5 | 2421213220322110120 |
6 | 35243343435412455 |
7 | 2215654355252462 |
oct | 240414220077263 |
9 | 43046230645248 |
10 | 11031124410035 |
11 | 357330116a934 |
12 | 12a1aa52b412b |
13 | 6202cc735622 |
14 | 2a1ca30749d9 |
15 | 141e28d8ba25 |
hex | a0862407eb3 |
11031124410035 has 16 divisors (see below), whose sum is σ = 13934743061760. Its totient is φ = 8360016426720.
The previous prime is 11031124409999. The next prime is 11031124410071. The reversal of 11031124410035 is 53001442113011.
It is an interprime number because it is at equal distance from previous prime (11031124409999) and next prime (11031124410071).
It is not a de Polignac number, because 11031124410035 - 224 = 11031107632819 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11031124409986 and 11031124410013.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 947837 + ... + 4791726.
It is an arithmetic number, because the mean of its divisors is an integer number (870921441360).
Almost surely, 211031124410035 is an apocalyptic number.
11031124410035 is a deficient number, since it is larger than the sum of its proper divisors (2903618651725).
11031124410035 is a wasteful number, since it uses less digits than its factorization.
11031124410035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5759818.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 11031124410035 its reverse (53001442113011), we get a palindrome (64032566523046).
The spelling of 11031124410035 in words is "eleven trillion, thirty-one billion, one hundred twenty-four million, four hundred ten thousand, thirty-five".
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