11031219993 has 4 divisors (see below), whose sum is σ = 14708293328. Its totient is φ = 7354146660.

The previous prime is 11031219971. The next prime is 11031220001. The reversal of 11031219993 is 39991213011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11031219993 - 2⁵ = 11031219961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11031219193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1838536663 + ... + 1838536668.

It is an arithmetic number, because the mean of its divisors is an integer number (3677073332).

Almost surely, 2^11031219993 is an apocalyptic number.

It is an amenable number.

11031219993 is a deficient number, since it is larger than the sum of its proper divisors (3677073335).

11031219993 is an equidigital number, since it uses as much as digits as its factorization.

11031219993 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3677073334.

The product of its (nonzero) digits is 13122, while the sum is 39.

It can be divided in two parts, 110312 and 19993, that added together give a triangular number (130305 = T₅₁₀).

The spelling of 11031219993 in words is "eleven billion, thirty-one million, two hundred nineteen thousand, nine hundred ninety-three".