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110312340343081 is a prime number
BaseRepresentation
bin11001000101010000010111…
…110111000100100100101001
3112110120202102200000012010221
4121011100113313010210221
5103424324133111434311
61030340442313210041
732143542425602642
oct3105202767044451
9473522380005127
10110312340343081
1132170223317938
121045732b700921
134972541919406
141d35207d766c9
15cb472546e671
hex645417dc4929

110312340343081 has 2 divisors, whose sum is σ = 110312340343082. Its totient is φ = 110312340343080.

The previous prime is 110312340342991. The next prime is 110312340343223. The reversal of 110312340343081 is 180343043213011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 110199500784025 + 112839559056 = 10497595^2 + 335916^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110312340343081 is a prime.

It is a super-2 number, since 2×1103123403430812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (110312340343981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55156170171540 + 55156170171541.

It is an arithmetic number, because the mean of its divisors is an integer number (55156170171541).

Almost surely, 2110312340343081 is an apocalyptic number.

It is an amenable number.

110312340343081 is a deficient number, since it is larger than the sum of its proper divisors (1).

110312340343081 is an equidigital number, since it uses as much as digits as its factorization.

110312340343081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 34.

Adding to 110312340343081 its reverse (180343043213011), we get a palindrome (290655383556092).

The spelling of 110312340343081 in words is "one hundred ten trillion, three hundred twelve billion, three hundred forty million, three hundred forty-three thousand, eighty-one".