Base | Representation |
---|---|
bin | 11001000101010001010010… |
… | …110111100101000111010001 |
3 | 112110120211222122211211210101 |
4 | 121011101102313211013101 |
5 | 103424333200031111423 |
6 | 1030341124440132401 |
7 | 32143606106430226 |
oct | 3105212267450721 |
9 | 473524878754711 |
10 | 110313330332113 |
11 | 32170691123297 |
12 | 10457567167101 |
13 | 497266ba5ca3c |
14 | 1d3529d63994d |
15 | cb47823247ad |
hex | 645452de51d1 |
110313330332113 has 2 divisors, whose sum is σ = 110313330332114. Its totient is φ = 110313330332112.
The previous prime is 110313330332077. The next prime is 110313330332147. The reversal of 110313330332113 is 311233033313011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 105854610913489 + 4458719418624 = 10288567^2 + 2111568^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110313330332113 is a prime.
It is not a weakly prime, because it can be changed into another prime (110313330336113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55156665166056 + 55156665166057.
It is an arithmetic number, because the mean of its divisors is an integer number (55156665166057).
Almost surely, 2110313330332113 is an apocalyptic number.
It is an amenable number.
110313330332113 is a deficient number, since it is larger than the sum of its proper divisors (1).
110313330332113 is an equidigital number, since it uses as much as digits as its factorization.
110313330332113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4374, while the sum is 28.
Adding to 110313330332113 its reverse (311233033313011), we get a palindrome (421546363645124).
The spelling of 110313330332113 in words is "one hundred ten trillion, three hundred thirteen billion, three hundred thirty million, three hundred thirty-two thousand, one hundred thirteen".
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