Base | Representation |
---|---|
bin | 10100100011000010… |
… | …11110101101001001 |
3 | 1001110210112120010200 |
4 | 22101201132231021 |
5 | 140043020014213 |
6 | 5022345202413 |
7 | 540240262464 |
oct | 122141365511 |
9 | 31423476120 |
10 | 11031407433 |
11 | 4750a3a752 |
12 | 217a490409 |
13 | 106a5a3127 |
14 | 7691282db |
15 | 4486e5273 |
hex | 29185eb49 |
11031407433 has 6 divisors (see below), whose sum is σ = 15934255194. Its totient is φ = 7354271616.
The previous prime is 11031407417. The next prime is 11031407473. The reversal of 11031407433 is 33470413011.
It can be written as a sum of positive squares in only one way, i.e., 9989602704 + 1041804729 = 99948^2 + 32277^2 .
It is not a de Polignac number, because 11031407433 - 24 = 11031407417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11031407397 and 11031407406.
It is not an unprimeable number, because it can be changed into a prime (11031407473) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 612855960 + ... + 612855977.
It is an arithmetic number, because the mean of its divisors is an integer number (2655709199).
Almost surely, 211031407433 is an apocalyptic number.
It is an amenable number.
11031407433 is a deficient number, since it is larger than the sum of its proper divisors (4902847761).
11031407433 is a wasteful number, since it uses less digits than its factorization.
11031407433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1225711943 (or 1225711940 counting only the distinct ones).
The product of its (nonzero) digits is 3024, while the sum is 27.
The spelling of 11031407433 in words is "eleven billion, thirty-one million, four hundred seven thousand, four hundred thirty-three".
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