Base | Representation |
---|---|
bin | 1010000010001101001000… |
… | …1100001000000010000001 |
3 | 1110001202002220111211002002 |
4 | 2200203102030020002001 |
5 | 2421231042104110423 |
6 | 35244254043433345 |
7 | 2216052041063405 |
oct | 240432214100201 |
9 | 43052086454062 |
10 | 11033002410113 |
11 | 357408525a112 |
12 | 12a232a225855 |
13 | 62053b835688 |
14 | 2a2000653105 |
15 | 141ed8ba1228 |
hex | a08d2308081 |
11033002410113 has 2 divisors, whose sum is σ = 11033002410114. Its totient is φ = 11033002410112.
The previous prime is 11033002410061. The next prime is 11033002410127. The reversal of 11033002410113 is 31101420033011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6987204062224 + 4045798347889 = 2643332^2 + 2011417^2 .
It is a cyclic number.
It is not a de Polignac number, because 11033002410113 - 232 = 11028707442817 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (11033002410193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5516501205056 + 5516501205057.
It is an arithmetic number, because the mean of its divisors is an integer number (5516501205057).
Almost surely, 211033002410113 is an apocalyptic number.
It is an amenable number.
11033002410113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11033002410113 is an equidigital number, since it uses as much as digits as its factorization.
11033002410113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 11033002410113 its reverse (31101420033011), we get a palindrome (42134422443124).
The spelling of 11033002410113 in words is "eleven trillion, thirty-three billion, two million, four hundred ten thousand, one hundred thirteen".
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