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110331031010323 is a prime number
BaseRepresentation
bin11001000101100001110001…
…111010010011110000010011
3112110122112200020210110111211
4121011201301322103300103
5103430130422414312243
61030353213111120551
732145103541626114
oct3105416172236023
9473575606713454
10110331031010323
1132178144754872
121045aa87073157
13497422cc6c126
141d3609c3cc20b
15cb4e6b2a4d9d
hex645871e93c13

110331031010323 has 2 divisors, whose sum is σ = 110331031010324. Its totient is φ = 110331031010322.

The previous prime is 110331031010257. The next prime is 110331031010327. The reversal of 110331031010323 is 323010130133011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 110331031010323 - 213 = 110331031002131 is a prime.

It is a super-2 number, since 2×1103310310103232 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110331031010294 and 110331031010303.

It is not a weakly prime, because it can be changed into another prime (110331031010327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55165515505161 + 55165515505162.

It is an arithmetic number, because the mean of its divisors is an integer number (55165515505162).

Almost surely, 2110331031010323 is an apocalyptic number.

110331031010323 is a deficient number, since it is larger than the sum of its proper divisors (1).

110331031010323 is an equidigital number, since it uses as much as digits as its factorization.

110331031010323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 110331031010323 its reverse (323010130133011), we get a palindrome (433341161143334).

The spelling of 110331031010323 in words is "one hundred ten trillion, three hundred thirty-one billion, thirty-one million, ten thousand, three hundred twenty-three".