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11033114041 is a prime number
BaseRepresentation
bin10100100011001111…
…11111010110111001
31001110220202021011101
422101213333112321
5140043434122131
65022445531401
7540260631145
oct122147772671
931426667141
1011033114041
1147519a5974
12217ab73b61
13106aa4cb61
14769450225
15448930c61
hex2919ff5b9

11033114041 has 2 divisors, whose sum is σ = 11033114042. Its totient is φ = 11033114040.

The previous prime is 11033114033. The next prime is 11033114137. The reversal of 11033114041 is 14041133011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7358208400 + 3674905641 = 85780^2 + 60621^2 .

It is a cyclic number.

It is not a de Polignac number, because 11033114041 - 23 = 11033114033 is a prime.

It is a super-2 number, since 2×110331140412 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11033114441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5516557020 + 5516557021.

It is an arithmetic number, because the mean of its divisors is an integer number (5516557021).

Almost surely, 211033114041 is an apocalyptic number.

It is an amenable number.

11033114041 is a deficient number, since it is larger than the sum of its proper divisors (1).

11033114041 is an equidigital number, since it uses as much as digits as its factorization.

11033114041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 11033114041 its reverse (14041133011), we get a palindrome (25074247052).

The spelling of 11033114041 in words is "eleven billion, thirty-three million, one hundred fourteen thousand, forty-one".