Base | Representation |
---|---|
bin | 10000000011100010100… |
… | …001011011010001010001 |
3 | 10220110211201020212220110 |
4 | 100003202201123101101 |
5 | 121034040340303131 |
6 | 2202504330031533 |
7 | 142466046416610 |
oct | 20034241332121 |
9 | 3813751225813 |
10 | 1103312041041 |
11 | 395a0397a4a1 |
12 | 1599b4b785a9 |
13 | 80071015182 |
14 | 3b5872d9877 |
15 | 1da76631646 |
hex | 100e285b451 |
1103312041041 has 16 divisors (see below), whose sum is σ = 1683962273664. Its totient is φ = 629442194304.
The previous prime is 1103312041033. The next prime is 1103312041063. The reversal of 1103312041041 is 1401402133011.
It is not a de Polignac number, because 1103312041041 - 23 = 1103312041033 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a junction number, because it is equal to n+sod(n) for n = 1103312040999 and 1103312041017.
It is not an unprimeable number, because it can be changed into a prime (1103312041241) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 42562950 + ... + 42588863.
It is an arithmetic number, because the mean of its divisors is an integer number (105247642104).
Almost surely, 21103312041041 is an apocalyptic number.
It is an amenable number.
1103312041041 is a deficient number, since it is larger than the sum of its proper divisors (580650232623).
1103312041041 is an equidigital number, since it uses as much as digits as its factorization.
1103312041041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 85152440.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 1103312041041 its reverse (1401402133011), we get a palindrome (2504714174052).
The spelling of 1103312041041 in words is "one trillion, one hundred three billion, three hundred twelve million, forty-one thousand, forty-one".
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