Base | Representation |
---|---|
bin | 10000000011100100001… |
… | …101001110110010010001 |
3 | 10220110220200102122220112 |
4 | 100003210031032302101 |
5 | 121034120104121312 |
6 | 2202511215451105 |
7 | 142466541551522 |
oct | 20034415166221 |
9 | 3813820378815 |
10 | 1103340301457 |
11 | 395a18921a09 |
12 | 159a02526a95 |
13 | 80076b2b404 |
14 | 3b58ad74849 |
15 | 1da78d64d22 |
hex | 100e434ec91 |
1103340301457 has 2 divisors, whose sum is σ = 1103340301458. Its totient is φ = 1103340301456.
The previous prime is 1103340301417. The next prime is 1103340301487. The reversal of 1103340301457 is 7541030433011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1056463288336 + 46877013121 = 1027844^2 + 216511^2 .
It is an emirp because it is prime and its reverse (7541030433011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1103340301457 - 232 = 1099045334161 is a prime.
It is not a weakly prime, because it can be changed into another prime (1103340301417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551670150728 + 551670150729.
It is an arithmetic number, because the mean of its divisors is an integer number (551670150729).
Almost surely, 21103340301457 is an apocalyptic number.
It is an amenable number.
1103340301457 is a deficient number, since it is larger than the sum of its proper divisors (1).
1103340301457 is an equidigital number, since it uses as much as digits as its factorization.
1103340301457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 32.
Adding to 1103340301457 its reverse (7541030433011), we get a palindrome (8644370734468).
The spelling of 1103340301457 in words is "one trillion, one hundred three billion, three hundred forty million, three hundred one thousand, four hundred fifty-seven".
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