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1103340301457 is a prime number
BaseRepresentation
bin10000000011100100001…
…101001110110010010001
310220110220200102122220112
4100003210031032302101
5121034120104121312
62202511215451105
7142466541551522
oct20034415166221
93813820378815
101103340301457
11395a18921a09
12159a02526a95
1380076b2b404
143b58ad74849
151da78d64d22
hex100e434ec91

1103340301457 has 2 divisors, whose sum is σ = 1103340301458. Its totient is φ = 1103340301456.

The previous prime is 1103340301417. The next prime is 1103340301487. The reversal of 1103340301457 is 7541030433011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1056463288336 + 46877013121 = 1027844^2 + 216511^2 .

It is an emirp because it is prime and its reverse (7541030433011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1103340301457 - 232 = 1099045334161 is a prime.

It is not a weakly prime, because it can be changed into another prime (1103340301417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551670150728 + 551670150729.

It is an arithmetic number, because the mean of its divisors is an integer number (551670150729).

Almost surely, 21103340301457 is an apocalyptic number.

It is an amenable number.

1103340301457 is a deficient number, since it is larger than the sum of its proper divisors (1).

1103340301457 is an equidigital number, since it uses as much as digits as its factorization.

1103340301457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 32.

Adding to 1103340301457 its reverse (7541030433011), we get a palindrome (8644370734468).

The spelling of 1103340301457 in words is "one trillion, one hundred three billion, three hundred forty million, three hundred one thousand, four hundred fifty-seven".