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1103414042113 is a prime number
BaseRepresentation
bin10000000011101000100…
…110100001111000000001
310220111002211012002001221
4100003220212201320001
5121034242443321423
62202522412155041
7142501425415045
oct20035046417001
93814084162057
101103414042113
11395a565083a9
12159a23168a81
13800891a9736
143b596a8c025
151da8057de5d
hex100e89a1e01

1103414042113 has 2 divisors, whose sum is σ = 1103414042114. Its totient is φ = 1103414042112.

The previous prime is 1103414042077. The next prime is 1103414042119. The reversal of 1103414042113 is 3112404143011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1080803506689 + 22610535424 = 1039617^2 + 150368^2 .

It is a cyclic number.

It is not a de Polignac number, because 1103414042113 - 221 = 1103411944961 is a prime.

It is not a weakly prime, because it can be changed into another prime (1103414042119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551707021056 + 551707021057.

It is an arithmetic number, because the mean of its divisors is an integer number (551707021057).

Almost surely, 21103414042113 is an apocalyptic number.

It is an amenable number.

1103414042113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1103414042113 is an equidigital number, since it uses as much as digits as its factorization.

1103414042113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1103414042113 its reverse (3112404143011), we get a palindrome (4215818185124).

The spelling of 1103414042113 in words is "one trillion, one hundred three billion, four hundred fourteen million, forty-two thousand, one hundred thirteen".