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11034402433 is a prime number
BaseRepresentation
bin10100100011011001…
…11001111010000001
31001111000011201111121
422101230321322001
5140044301334213
65022533312241
7540304605325
oct122154717201
931430151447
1011034402433
1147526a595a
12217b495681
13106b0b1412
147696a7985
15448ad788d
hex291b39e81

11034402433 has 2 divisors, whose sum is σ = 11034402434. Its totient is φ = 11034402432.

The previous prime is 11034402403. The next prime is 11034402461. The reversal of 11034402433 is 33420443011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8297752464 + 2736649969 = 91092^2 + 52313^2 .

It is an emirp because it is prime and its reverse (33420443011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11034402433 - 217 = 11034271361 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11034402398 and 11034402407.

It is not a weakly prime, because it can be changed into another prime (11034402403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5517201216 + 5517201217.

It is an arithmetic number, because the mean of its divisors is an integer number (5517201217).

Almost surely, 211034402433 is an apocalyptic number.

It is an amenable number.

11034402433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11034402433 is an equidigital number, since it uses as much as digits as its factorization.

11034402433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 11034402433 its reverse (33420443011), we get a palindrome (44454845444).

The spelling of 11034402433 in words is "eleven billion, thirty-four million, four hundred two thousand, four hundred thirty-three".