Base | Representation |
---|---|
bin | 10100100011011010… |
… | …00000101000110011 |
3 | 1001111000020010022201 |
4 | 22101231000220303 |
5 | 140044303230003 |
6 | 5022534044031 |
7 | 540305051602 |
oct | 122155005063 |
9 | 31430203281 |
10 | 11034430003 |
11 | 4752714643 |
12 | 217b4a9617 |
13 | 106b0c0b2c |
14 | 7696b3a39 |
15 | 448ae0b1d |
hex | 291b40a33 |
11034430003 has 4 divisors (see below), whose sum is σ = 11089879600. Its totient is φ = 10978980408.
The previous prime is 11034429971. The next prime is 11034430007. The reversal of 11034430003 is 30003443011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11034430003 - 25 = 11034429971 is a prime.
It is a super-2 number, since 2×110344300032 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11034430007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27724500 + ... + 27724897.
It is an arithmetic number, because the mean of its divisors is an integer number (2772469900).
Almost surely, 211034430003 is an apocalyptic number.
11034430003 is a deficient number, since it is larger than the sum of its proper divisors (55449597).
11034430003 is an equidigital number, since it uses as much as digits as its factorization.
11034430003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55449596.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 11034430003 its reverse (30003443011), we get a palindrome (41037873014).
The spelling of 11034430003 in words is "eleven billion, thirty-four million, four hundred thirty thousand, three".
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