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1104042021131 = 7222531469819
BaseRepresentation
bin10000000100001110000…
…010000101000100001011
310220112201120211201100002
4100010032002011010023
5121042034224134011
62203105004033215
7142523122224500
oct20041602050413
93815646751302
101104042021131
11396248a36325
12159b7953280b
138015932045a
143b6162394a7
151daba776c3b
hex1010e08510b

1104042021131 has 6 divisors (see below), whose sum is σ = 1284293779740. Its totient is φ = 946321732356.

The previous prime is 1104042021073. The next prime is 1104042021139. The reversal of 1104042021131 is 1311202404011.

It is not a de Polignac number, because 1104042021131 - 230 = 1102968279307 is a prime.

It is a super-2 number, since 2×11040420211312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1104042021139) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 11265734861 + ... + 11265734958.

It is an arithmetic number, because the mean of its divisors is an integer number (214048963290).

Almost surely, 21104042021131 is an apocalyptic number.

1104042021131 is a deficient number, since it is larger than the sum of its proper divisors (180251758609).

1104042021131 is an equidigital number, since it uses as much as digits as its factorization.

1104042021131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22531469833 (or 22531469826 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 1104042021131 its reverse (1311202404011), we get a palindrome (2415244425142).

The spelling of 1104042021131 in words is "one trillion, one hundred four billion, forty-two million, twenty-one thousand, one hundred thirty-one".

Divisors: 1 7 49 22531469819 157720288733 1104042021131