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1104042130041 = 3368014043347
BaseRepresentation
bin10000000100001110000…
…010011111101001111001
310220112201121001020201210
4100010032002133221321
5121042034241130131
62203105010233333
7142523123160144
oct20041602375171
93815647036653
101104042130041
11396249000134
12159b79585849
138015935abb6
143b61626705b
151daba799146
hex1010e09fa79

1104042130041 has 4 divisors (see below), whose sum is σ = 1472056173392. Its totient is φ = 736028086692.

The previous prime is 1104042130001. The next prime is 1104042130057. The reversal of 1104042130041 is 1400312404011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1104042130041 - 27 = 1104042129913 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1104042130001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 184007021671 + ... + 184007021676.

It is an arithmetic number, because the mean of its divisors is an integer number (368014043348).

Almost surely, 21104042130041 is an apocalyptic number.

It is an amenable number.

1104042130041 is a deficient number, since it is larger than the sum of its proper divisors (368014043351).

1104042130041 is an equidigital number, since it uses as much as digits as its factorization.

1104042130041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 368014043350.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 1104042130041 its reverse (1400312404011), we get a palindrome (2504354534052).

The spelling of 1104042130041 in words is "one trillion, one hundred four billion, forty-two million, one hundred thirty thousand, forty-one".

Divisors: 1 3 368014043347 1104042130041